My output should look like this: y1 y2 y3 y4 1 A 1 1 1 2 A 2 1 3 A 3 3 3 4 A 4 4 4 5 A 5 5 5 6 B 1 1 1 7 B 2 1 8 B 3 3 3 9 B 4 3 10 B 5 5 5 Any idea about how to use dplyr to achieve this goal? I am working on a server and can not change dplyr-version on the fly (It is 2 month old). the answer will be "it  fill () fill () fills the NA s (missing values) in selected columns ( dplyr::select () options could be used like in the below example with everything () ). Another possibility is to combine the by solution (shown further below) with dplyr: zoo This solution uses zoo alone. fill. I don't even understand lists or atomic vectors or any of that at this point. I want to fill in the NA based on the closest non-NA value "in front of" this NA. Products. In combination with mutate it can replace existing columns. Fills missing values in selected columns using the previous entry. If data is a vector, replace takes a single value. 1 Tidy way of NA management by groups? : Fill in missing values with previous or next value. Can someone be saved if they willingly live in sin? Preferable with one of the window-functions. Learn more at tidyverse.org . By clicking “Post Your Answer”, you agree to our terms of service, privacy policy and cookie policy. I found that a method I was hoping to publish is already known. data A data frame or vector. Complete a data frame with missing combinations - tidyr, If you supply fill , these values will also replace existing explicit missing values in the data set. Fills missing values in selected columns using the next or previous entry. This code shows how to fill gaps in a vector. Since data.table v1.12.4, the package has a nafill() funciton, similar to tidyr::fill() or zoo::na.locf() and you can do: There is also setnafill(), though not allowing for a group by, but multpile columns. Currently  Columns to fill..direction: Direction in which to fill missing values. View source: R/fill.R. What would be a proper way to retract emails sent to professors asking for help? If you need to do this repeatedly,  The zoo R package contains the na.locf function, which is a generic function for replacing each NA with the most recent non-NA value prior to it. Currently  I have a dataset like this 4 6 18 12 4 5 2 9 0 3 NA 13 11 NA 6 7 7 9 How I can fill the missing values using R? Missing values must be dropped or replaced in order to draw correct conclusion from the data. This is Direction in which to fill missing values. This on works: df %.% group_by(houseID) %.% mutate(p2 = na.locf(price,na.rm=F)). How to calculate the very special orbit of 2020 SO, Idiom or phrase to describe the worst of two situations, Construct a polyhedron from the coordinates of its vertices and calculate the area of each face. Filling missing values, @george if it is not just a pure R-question but rather something like "How can I impute missing values in my data set?" In a data.frame (or data.table), I would like to "fill forward" NAs with the closest previous non-NA value. It also lets us select the .direction either down (default) or up or updown or downup from where the missing value must be filled. Fill in missing values with previous or next value, Source: R/fill.R. Fill in missing values with previous or next value, Fills missing values in selected columns using the next or previous entry. Also note that na.locf0 (also defined in zoo) is like na.locf except it defaults to na.rm = FALSE and requires a single vector argument. fill in NA based on the last non-NA value for each group in R, This may have been answered before, but I don't know if it's been answered in a dplyr context. In dplyr I can replace NA with 0 using the following code. Exposure At Default: Calculating the present value. Replace NA with Zero in dplyr without using list(), What version of dplyr are you using? Fills missing values in selected columns using the previous entry. It returns a wide rather than long result: This solution could be combined with dplyr like this: Here is the input used for the examples above: REVISED Re-arranged and added more solutions. locf ( x ) # Apply na.locf function # 1 2 2 2 2 3 3 4. Revised dplyr/zoo solution to conform to latest changes dplyr. fill.Rd. The replace_na function now seems to be in tidyr . The following is an example: I would like to make a data frame like this: These all use na.locf from the zoo package. This is inspired by the SQL COALESCE function which does the same thing for NULLs. first down and then up) or "updown" (first up and then down). Replace NAs with specified values, dplyr::na_if() to replace specified values with NA s; dplyr::coalesce() to replaces NA s with values from other vectors. How do I replace NA values with zeros in an R dataframe? My question is I have a dataframe m as below. site design / logo © 2020 Stack Exchange Inc; user contributions licensed under cc by-sa. replace If data is a data frame, replace takes a list of values, with one value for each column that has NA values to be replaced. Replace missing values (NA) with most recent non-NA by group, How to write an effective developer resume: Advice from a hiring manager, Podcast 290: This computer science degree is brought to you by Big Tech, “Question closed” notifications experiment results and graduation, MAINTENANCE WARNING: Possible downtime early morning Dec 2/4/9 UTC (8:30PM…, Congratulations VonC for reaching a million reputation, Replace missing value with previous value, fill in NA based on the last non-NA value for each group in R. How to replace NA with most recent non-NA by group?